Notice:
The advice given on this site is based upon individual or quoted experience, yours may differ.
The Officers, Staff and members of this site only provide information based upon the concept that anyone utilizing this information does so at their own risk and holds harmless all contributors to this site.
Any ideas on how to test the power generated by a solar panel. I have a Coleman 5w hooked to my battery. I am not sure how much ,if any power it is generating?
hook a voltmeter to it. output in direct sunlight should be above 13 volts. make sure that there is a blocking diode so when the output drops below 12v that the battery does not discharge.
A 5w panel is a Trickle charger. Under ideal conditions and unregulated it will put out around 17-22 volts and about 0.3 amps. Don't be alarmed about the volts because the amp output is very low so It can't overcharge the battery You can check it with a multi meter for output. Make sure it has a blocking diode to prevent the battery from draining power back to the panel at night.Most have the diode built in. I have a 7.5w panel plugged in to a pick up I rarely use through through the winter and it does a great job of keeping the battery fully charged.
Scott-"IMPULSE"87'C25/SR/WK/Din.#5688 Sailing out of Glen Cove,L.I Sound
Solar panels are rated in watts but the number is misleading. If you purchase a 5W panel what that means its open circuit voltage multiplied by short circuit current. So if your 12VDC panel puts out 20VDC open circuit, the short circuit current will be 0.25A. So under load charging your battery, when the panel delivers 12VDC at 0.25A, it's actually delivering only 3W.
Yep, like I said, it's rated by Voc and Isc, so how else could they rate it? By maximum power transfer under load.
Assume you had a resistor that you could vary in resistance between say 100 Ohms and 2 Ohms. Connect the panel to the resistor with an ammeter in series and a voltmeter in parallel with the resistor.
At 100 Ohms and 20V (approx Voc), using Ohms Law V = IxR, the current would be 0.2A. 20x.2=4W
So now reduce the Ohms to 75, meaning more current, but a lower voltage. Say the voltage drops to 18V, the current is now 0.24A so power increases to 4.32W.
As we know from our calcs above at 12V we get about 0.25A so the equivalent resistance is about 48 Ohms. The power delivered to the battery is about 3W.
So we know that the panel is capable of producing ~60% more power but we can't harness it all for a 12V charging circuit using a direct connection or a simple on/off charge controller.
In our application we're charging up a battery that sets the output voltage, and as a result of that we're stuck with much less than peak current. But it's better than nothing!
There are some more complex and costly switching charge controllers but with a 5W panel, it's not cost justified. If you're a liveaboard with 200W or more, then it makes sense for sure.
Notice: The advice given on this site is based upon individual or quoted experience, yours may differ. The Officers, Staff and members of this site only provide information based upon the concept that anyone utilizing this information does so at their own risk and holds harmless all contributors to this site.